Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Confused! kindly explain, - Limit , continuity and differentiability - JEE Main-2

The function g\left ( x \right )= \frac{x}{2}+\frac{2}{x} has a local minimum at

  • Option 1)

    x=2

  • Option 2)

    x=-2

  • Option 3)

    x=0

  • Option 4)

    x=1

 

Answers (1)

best_answer

As we learnt in 

Rate Measurement -

Rate of any of variable with respect to time is rate of measurement. Means according to small change in time how much other factors change is rate measurement:

\Rightarrow \frac{dx}{dt},\:\frac{dy}{dt},\:\frac{dR}{dt},(linear),\:\frac{da}{dt}


\Rightarrow \frac{dS}{dt},\:\frac{dA}{dt}(Area)


\Rightarrow \frac{dV}{dt}(Volume)


\Rightarrow \frac{dV}{V}\times 100(percentage\:change\:in\:volume)

- wherein

Where dR / dt  means Rate of change of radius.

 

 g(x)=\frac{r}{2}+\frac{2}{x}

g{}'(x)=\frac{1}{2}-\frac{2}{x^{2}}

0=\frac{1}{2}-\frac{2}{x^{2}}

=>\Rightarrow x^{2}=4 \Rightarrow x=2


Option 1)

x=2

This is correct option

Option 2)

x=-2

This is incorrect option

Option 3)

x=0

This is incorrect option

Option 4)

x=1

This is incorrect option

Posted by

Plabita

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Mains 2025 session 1 registration deadline on November 22; apply on jeemain.nta.nic.in
anam-khan

BTech Admission 2025 Live: JEE Mains, SRMJEEE, MET registrations underway; MHT CET syllabus updates
anam-khan

Centre issues coaching guidelines, prohibits centres from using false claims like '100% selection'

Latest Question