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  • Confused! kindly explain, - Oscillations and Waves - JEE Main-4

A block is suspended from the ceiling of an elevator through a string having a linear mass density of 19.2\times 10^{-3} kg/m. Find the speed of wave if the elevator goes upward with 2m/s2

  • Option 1)

    50 m/s

  • Option 2)

    5 m/s

  • Option 3)

    10 m/s

  • Option 4)

    100 m/s

 

Answers (1)

T = m(g + a) = 4 (10 + 2 ) = 48 N

v = \sqrt \frac{T}{m} = \sqrt \frac{48}{19.2 X 10 ^{-3}} = 50 m/s

 

 

Speed of wave on string -

v= \sqrt{\frac{T}{\mu }}
 

- wherein

T= Tension in the string

\mu = linear mass density

 

 

 


Option 1)

50 m/s

This is correct.

Option 2)

5 m/s

This is incorrect.

Option 3)

10 m/s

This is incorrect.

Option 4)

100 m/s

This is incorrect.

Posted by

subam

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