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  • Confused! kindly explain, Two point charges +8q and -2q are located at x = 0 and x = L respectively. The location of a point on the x axis at which the net electric field due to these two point charges is zero is

Two point charges  +8q and  -2q are located at x = 0  and x = L respectively. The location of a point on the x axis at which the net electric field due to these two point charges is zero is

  • Option 1)

    8L

  • Option 2)

    4L

  • Option 3)

    2L

  • Option 4)

    L/4

 

Answers (2)

best_answer

As we learnt in

Superposition of Electric field -

The resultant electric field at any point is equal to the vector sum of all the electric fields.

 

- wherein

\vec{E}=\vec{E_{1}}+\vec{E_{2}}+\vec{E_{3}}+\cdots\vec{E_{n}}

 

 

Resultant intensity = 0

 

\frac{1}{4\pi \varepsilon _{0}}\frac{8q}{\left ( L+d \right )^{2}}-\frac{1}{4\pi \varepsilon _{0}}\frac{2q}{d^{2}}= 0

or\: \: \: \left ( L+d^{2} \right )= 4d^{2}

or\: \: \: d=L

Distance \: \: from \: \: origin \: \: = 2L


Option 1)

8L

Incorrect

Option 2)

4L

Incorrect

Option 3)

2L

Correct

Option 4)

L/4

Incorrect

Posted by

Aadil

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