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Consider a galvanometer shunted with 5 \Omega resistance and 2 \% of current passes through it. What is the resistance of the given galvanometer?
 
Option: 1 245 \Omega
Option: 2 344 \Omega
Option: 3 300 \Omega
Option: 4 226 \Omega

Answers (1)

best_answer


I_{g}= \frac{2}{100}\times I= 0\cdot 02I
I-I_{g}=0\cdot 98I
I_{g}R_{G}=\left ( I-I_{9} \right )s
\left ( 0\cdot 02I \right )\times R_{G}= \left ( 0\cdot 98 \right )I\times 5
R_{G}=49\times 5= 245\: \Omega
The correct option is (1)

Posted by

vishal kumar

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