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  • Consider an n – p – n transistor amplifier in common emitter configuration. The current gain in the transistor is 100. If the collector current changes by 1 mA. What will be the change

Consider an n – p – n transistor amplifier in common emitter configuration. The current gain in the transistor is 100. If the collector current changes by 1 mA. What will be the change in emitter current?

Option: 1

1.1 mA


Option: 2

1.01 mA


Option: 3

0.01 mA


Option: 4

10 mA


Answers (1)

best_answer

Here, \mathrm{\beta=100, \Delta \mathrm{I}_{\mathrm{C}}=1 \mathrm{~mA}}

As \mathrm{\alpha=\frac{\beta}{1+\beta}=\frac{100}{101}}

\mathrm{\begin{array}{ll} \alpha=\frac{\Delta \mathrm{I}_{\mathrm{C}}}{\Delta \mathrm{I}_{\mathrm{E}}} & \text { or } \quad \frac{100}{101}=\frac{1 \mathrm{~mA}}{\Delta \mathrm{I}_{\mathrm{E}}} \\ \therefore \Delta \mathrm{I}_{\mathrm{E}}=1.01 \mathrm{~mA} \end{array}}

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manish

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