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  • Consider the consecutive reaction <img alt="\mathrm{A \stackrel{k_{1}}{\longrightarrow} B \stackrel{k_{2}}{\rightarrow}C}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7BA%

Consider the consecutive reaction
\mathrm{A \stackrel{k_{1}}{\longrightarrow} B \stackrel{k_{2}}{\rightarrow}C}. Given that rate constant \mathrm{k_{1} \, \& \, k_{2}} are \mathrm{0.01\, s^{-1}\: \&\: 0.05\, s^{-1}} respectively. What is the overall rate constant \mathrm{\left ( k \right )} for the consecutive reactions?

Option: 1

0.08\, s^{-1}


Option: 2

0.02\, s^{-1}


Option: 3

0.01 \mathrm{~s}^{-1}


Option: 4

\mathrm{0.005\, s^{-1}}


Answers (1)

best_answer

for consecutive reactions the rate constant (k)  for the overall reaction is determined by the slowstep reaction as it is late determining step.so,from the value of rate constant \mathrm{k_{1}<k_{2}} hence first rate is the date determining step. 
therefore

\mathrm{k_{\text {overall }}=k_{1}=0.01\, s^{-1}}

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Anam Khan

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