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  • Consider the following pairs of electrons <img alt="\mathrm{(A) \; \; (a) \; \; n=3,1=1, m_{1}=1, m_{s}=+\frac{1}{2}}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%

Consider the following pairs of electrons

\mathrm{(A) \; \; (a) \; \; n=3,1=1, m_{1}=1, m_{s}=+\frac{1}{2}}
          \mathrm{(b) \; \; \mathrm{n}=3,1=2, \mathrm{~m}_{1}=1, \mathrm{~m}_{\mathrm{s}}=+\frac{1}{2}}

\mathrm{(B)\; \; (a) \; \; n=3,1=2, m_{1}=-2, m_{s}=-\frac{1}{2}}
          \mathrm{(b) \; \; n=3,1=2, m_{1}=-1, m_{s}=-\frac{1}{2}}

\mathrm{(C) \; \; (a)\; \; \mathrm{n}=4,1=2, \mathrm{~m}_{\mathrm{l}}=2, \mathrm{~m}_{\mathrm{s}}=+\frac{1}{2}}
          \mathrm{(b)\; \; \mathrm{n}=3,1=2, \mathrm{~m}_{\mathrm{l}}=2, \mathrm{~m}_{\mathrm{s}}=+\frac{1}{2}}

The pairs of electrons present in degenerate orbitals is / are :

Option: 1

\mathrm{Only\, (A)}


Option: 2

\mathrm{Only\: (B)}


Option: 3

\mathrm{Only \, (C)}


Option: 4

\mathrm{(B) \, and \, (C)}


Answers (1)

best_answer

As we have learnt,

Orbitals having same \mathrm{\left ( n+l \right )}  value are degenerate.

Since, only the pair of elections given in Option (B) have same value of  \mathrm{\left ( n+l \right )}, they are degenerate.

Hence, the correct answer is Option (2)

Posted by

avinash.dongre

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