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Consider the reaction of 2-Bromobutane with alc. KOH and \mathrm{t-BuO^{\ominus }K^{\bigoplus }} as given below

(\mathrm{t-BuO^{\ominus }K^{\bigoplus }} is Potassium Tertiary Butoxide)

Option: 1

Identical


Option: 2

Chain isomers


Option: 3

Positional isomers


Option: 4

Not isomeric


Answers (1)

best_answer

\mathrm{t-BuO^-} is a bulky base and extracts least hindred \mathrm{\beta -H} from the substrate giving the Hoffman's alkene while \mathrm{alc.\ KOH} will give the Saytzeff's product

(P) and (Q) are thus positional isomers .

Therefore, the correct answer is Option (3).

Posted by

himanshu.meshram

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