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Cromium metal can be plated out from an acidic solution containing \mathrm{CrO}_3 by the equation given below find how many grams of chromium plated out by 26500 coulombs.

\mathrm{\mathrm{CrO}_3+6 \mathrm{H}^{+}+6 e^{-} \rightarrow \mathrm{Cr}+3 \mathrm{H}_2 \mathrm{O}}

Option: 1

2.5 g


Option: 2

2.3 g


Option: 3

1.6 g


Option: 4

1.8 g


Answers (1)

best_answer

\mathrm{\mathrm{\text Eq ~wt. ~of ~Cr} = \frac{Atomic ~weight}{Change ~In ~oxidation ~per ~mole}}

                             \mathrm{=\frac{52}{6}}

\mathrm{96500 \text { coulomb }=\frac{52}{6} \mathrm{~gm}(\mathrm{Cr})}

\mathrm{26500 \text { C will deposite}=\frac{52}{6} \times \frac{26500}{96500} \mathrm{gm}}

\mathrm{=2.3 \mathrm{~g}}

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chirag

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