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  • Current in resistance is 1 A, then:                                            

Current in resistance is 1 A, then:
                                                      

Option: 1

\mathrm{V}_{\mathrm{s}}=5 \mathrm{~V}


Option: 2

impedance of network is 5 \Omega


Option: 3

power factor of given circuit is (0.6) lagging (current is lagging)


Option: 4

All of the above


Answers (1)

best_answer


\mathrm{V}_{\mathrm{s}}^2=(3)^2+(8-4)^2 ; \mathrm{V}_{\mathrm{s}}=5 \mathrm{~V}

Now, \mathrm{\mathrm{Z}=\frac{\mathrm{V}_{\mathrm{s}}}{\mathrm{I}}=\frac{5}{1}=5 \Omega Also, \mathrm{V}_{\mathrm{R}}=\mathrm{IR} or \quad \mathrm{R}=\frac{3}{1}=3 \Omega So, \quad}
\mathrm{ P F=\frac{R}{Z}=\frac{3}{5}=0.6\ as V_L>V_C \Rightarrow \mathrm{I} \, \, lags \mathrm{V},}
 so this is a lagging nature.

Posted by

Rishabh

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