Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Decarboxylation of all six possible forms of diaminobenzoic acids <img alt="\mathrm{C}_{6} \mathrm{H}_{3}\left(\mathrm{NH}_{2}\right)_{2} \mathrm{COOH}" src="https://entrancecorner.oncodecogs.

Decarboxylation of all six possible forms of diaminobenzoic acids \mathrm{C}_{6} \mathrm{H}_{3}\left(\mathrm{NH}_{2}\right)_{2} \mathrm{COOH} yields three products A, B and C. Three acids give a product 'A', two acids gives a product 'B' and one acid give a product 'C'  The melting point of product 'C' is

Option: 1

63^{\circ} \mathrm{C}


Option: 2

90^{\circ} \mathrm{C}


Option: 3

104^{\circ} \mathrm{C}


Option: 4

142^{\circ} \mathrm{C}


Answers (1)

best_answer

6 forms of diaminobenzoic acid are

C has a melting point of 142^{\circ }\text{C}

Hence, Option(4) is correct.

Posted by

shivangi.shekhar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025: BTech CSE cut-offs for PwD candidates at NITs make entry easy; top institutes still selective
anam-khan

73 or 99 percentile? JEE Main result questioned, J-K candidate says, ‘Don’t create hype’
anam-khan

JEE Main 2025: 11 from Kota coaching centres among 24 students with 100 percentile

Latest Question