Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Determine the radius of the circle inscribed in the triangle formed by the lines x = 0, y = 0 and 4x + 3y − 24 = 0.   Option: 1</strong

Determine the radius of the circle inscribed in the triangle formed by the lines x = 0, y = 0 and 4x + 3y − 24 = 0. 

 

Option: 1

2


Option: 2

4


Option: 3

\frac{5}{2}


Option: 4

\frac{1}{2}


Answers (1)

best_answer

Points of intersection are A (0, 0), B (0, 8) and C (6, 0). 

a=B C=\sqrt{36+64}=10 \\ b=C A=6 \\ c=A B=8 \\


\Rightarrow 2 s=10+6+8=24 \\ \Rightarrow s=12 \\


\Rightarrow \Delta=\sqrt{s(s-a)(s-b)(s-c)}=\sqrt{12 \times 2 \times 6 \times 4}=24 \\

Thus, r=\frac{\Delta}{s}=\frac{24}{12}=2

 

Posted by

shivangi.bhatnagar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026 Registration LIVE: NTA session 1 applications close on November 27; apply at jeemain.nta.nic.in
anam-khan

JEE 2026: IIT admissions show major shift toward AI, data science, away from core engineering courses
anam-khan

JEE Main 2026: NIT Delhi cut-offs for BTech courses show ever-increasing demands for AI, computer skills

Latest Question