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Directrix of parabola 5 x^2+30 x+2 y+59=0 is 

Option: 1

x-2 y-5=0
 


Option: 2

\mathrm{x+2y+10=0}
 


Option: 3

\mathrm{10y+69=0}
 


Option: 4

\mathrm{x-2y+5=0}


Answers (1)

best_answer

Parabola is 5 x^2+30 x+2 y+59=0

    \Rightarrow \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \quad(x+3)^2=-\frac{2}{5}(y+7)

                           

In order to shift the origin to (-3,-7)

Putting        x=X-3, y=Y-7, we get X^2=-\frac{2}{5} Y

vertext A is (-3,-7), a=\frac{1}{4} \times \frac{2}{5}=\frac{1}{10}

Directrix                         Y=\frac{1}{10}

\Rightarrow y+7=\frac{1}{10} \Rightarrow 10 y+69=0

Posted by

Nehul

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