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\mathrm{CuS} dissolves in \mathrm{HNO_3}  to form two solids A and B. B is monoatomic pale yellow solid that reacts further with \mathrm{HNO_3} if heated for a long time to form C which makes the solution blue. What is A, B and C?

Option: 1

\mathrm{A: Cu(NO_3)_2 B: S \: \: C: CuSO_4}


Option: 2

\mathrm{A: Cu(NO)_3 \ \ B: CuCl \: \: C: CuSO_4}


Option: 3

\mathrm{A: Cu(NO_3)_2 \: B: S \: \: C: CuCl}


Option: 4

\mathrm{A: Cu(NO_3)_2 \: B: CuCl \: \: C: CuSO_4}


Answers (1)

best_answer

Copper sulphide dissolves in nitric acid due to the formation of copper nitrate.

\mathrm{3CuS + 8HNO_3 \rightarrow 3Cu(NO_3)_2 + 2NO + 3S + 4H_2O}

On heating the reaction mixture for long time, sulphur is oxidized to sulphate and copper sulphate is formed and the solution turns blue.

\mathrm{S + 2HNO_3 \rightarrow H_2SO_4 + 2NO}

\mathrm{H_2SO_4(aq) + Cu(NO_3)_2(aq) \rightarrow CuSO_4(aq) + 2HNO_3(aq)}

Hence option 1 is correct.

Posted by

manish painkra

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