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Domain of \frac{1}{\sqrt{x^2+2}}  is

Option: 1

R


Option: 2

x\neq -2


Option: 3

x\neq \pm \sqrt{2}


Option: 4

None of these


Answers (1)

best_answer

\sqrt{x^2+2}\neq 0  and  x^2+2>0

Now, x^2+2\geq 2 for any real value of x.

So,  \sqrt{x^2+2}\neq 0  and x^2+2>0 for all real value of x.

So, domain is R.

Posted by

himanshu.meshram

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