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  • Electric potential is given by  volt. The electric field at point  (2,

Electric potential is given by \mathrm{ v=3 x^2} volt. The electric field at point  (2,0,4) m  will be -

Option: 1

12 \mathrm{Vm}^{-1}  directed along negative x-axes.


Option: 2

10 \mathrm{vm}^{-1}  directed along negative x-axes.


Option: 3

12 \mathrm{vm}^{-1}  directed along positive x-axes.


Option: 4

10 \mathrm{vm}^{-1}  directed along positive y-axes..


Answers (1)

best_answer

\mathrm{\vec{E}_x} \mathrm{=-\frac{d v}{d x} \hat{i}}
\mathrm{=-\frac{d}{d x}\left[3 x^2\right] \hat{i} }
\mathrm{ \vec{E}_x=-6 x \hat{i} }
at point (2,0,4) \mathrm{\Rightarrow \vec{E}_x} \mathrm{=-12 \hat{i} }\mathrm{v} / \mathrm{m}
 

Posted by

Ritika Harsh

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