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Equal weights of methane and oxygen are mixed in an empty container at 25^{\circ} \mathrm{C}. The fraction of the total pression exerted by oxygen is -

Option: 1

1 / 3


Option: 2

1 / 2


Option: 3

2 / 3


Option: 4

273 / 298


Answers (1)

best_answer

If X g of both oxygen and methane are mixed then,

              \mathrm{mole ~of ~oxygen =\frac{x}{32}}

              \mathrm{mole ~of ~methane =\frac{x}{16}}

\mathrm{\Rightarrow \text { Mole fraction of oxygen }=\frac{x / 32}{x / 32+x / 16}=\frac{1}{3}}

According to law of partial pressure,

partial pressure of oxygen \mathrm{\left(\mathrm{PO}_2\right)=} mole fraction x total pressure
\mathrm{ \Rightarrow \frac{P{\mathrm{O}_2}}{P}=\frac{1}{3} }

Posted by

manish painkra

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