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  • Equation of chord  of circle <img alt="\mathrm{x^2+y^2=2}" src="https://entrancecorner.

Equation of chord (\mathrm{AB}) of circle \mathrm{x^2+y^2=2} passing through the point \mathrm{P(2,2)}, such that \mathrm{\frac{P B}{P A}=3}, is
 

Option: 1

\mathrm{ x=3 y}
 


Option: 2

\mathrm{ x=y}


Option: 3

\mathrm{ y-2=\sqrt{3}(x-2)}


Option: 4

none of these
 


Answers (1)

best_answer

\mathrm{As\ \ \frac{P B}{P A}=3 \Rightarrow A B=(P B-P A)=2 \sqrt{2} \quad\left\{Q \quad(P A)(P B)=P T^2\right\}}
As point P is (2,2) and the given circle \mathrm{x^2+y^2=2} has diameter 2 \sqrt{2}.
\mathrm{\Rightarrow A B} is diameter of the circle.
\Rightarrow Line must pass through the centre (0,0) also.

Posted by

Ritika Kankaria

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