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 Equation of parabola having it's focus at \mathrm{S(2,0)} and one extremity of it's latus rectum as \mathrm{(2,2)} is

Option: 1

\mathrm{y}^{2}=4(3-\mathrm{x})


Option: 2

\mathrm{y}^{2}=4(1-\mathrm{x})


Option: 3

\mathrm{y^{2}=8(3-x)}


Option: 4

\mathrm{y}^{2}=8(3-\mathrm{x})


Answers (1)

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Clearly, the other extremity of latus rectum is (2,2). It's axis is x-axis.

Corresponding value of \mathrm{a=\frac{2-0}{2}=1}
Hence it's vertex is (1,0)$ or $(3,0)
Thus it's equation is

\mathrm{y^{2}=4(x-1) \text { or } y^{2}=4(x-3)}.

Posted by

Nehul

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