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  • Equation of the parabola with its vertex at (1, 1) and (3,1) focus isOption: 1 <img alt="\mathrm{(x-1)^2=8(y-1)}" src="https://entrancecorner.oncodec

Equation of the parabola with its vertex at (1, 1) and (3,1) focus is

Option: 1

\mathrm{(x-1)^2=8(y-1)}


Option: 2

\mathrm{(y-1)^2=8(x-3)}


Option: 3

\mathrm{(y-1)^2=8(x-1)}


Option: 4

\mathrm{(x-3)^2=8(y-1)}


Answers (1)

best_answer

Given vertex of parabola \mathrm{(h, k) \equiv(1,1)} and its focus \mathrm{(a+h, k) \equiv(3,1)} or \mathrm{a+h=3} or \mathrm{a=2}. We know that as

the y-coordinates of vertex and focus are same, therefore axis of parabola is parallel to x-axis. Thus equation of the parabola

is \mathrm{(y-k)^2=4 a(x-h)} or \mathrm{(y-1)^2=4 \times 2(x-1)} or \mathrm{(y-1)^2=8(x-1)}

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Rishi

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