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  • Every series of hydrogen spectrum has an upper and lower limit in wavelength. The spectral series which has an upper limit of wavelength equal to 18752 Å is<strong

Every series of hydrogen spectrum has an upper and lower limit in wavelength. The spectral series which has an upper limit of wavelength equal to 18752 Å is

Option: 1

Balmer series


Option: 2

Lyman series


Option: 3

Paschen series


Option: 4

Pfund series


Answers (1)

best_answer

\mathrm{ \frac{1}{\lambda}=R\left[\frac{1}{n_1^2}-\frac{1}{n_2^2}\right] \Rightarrow \frac{1}{n_1^2}-\frac{1}{n_2^2}=\frac{1}{R \lambda}}
\mathrm{=\frac{1}{1.097 \times 10^7 \times 18752 \times 10^{-10}}=0.0486=\frac{7}{144} . \text { But }}

\mathrm{\frac{1}{3^2}-\frac{1}{4^2}=\frac{7}{144} \Rightarrow n_1=3 \text { and } n_2=4 \quad \text { (Paschen series) }}
 

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SANGALDEEP SINGH

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