Get Answers to all your Questions

header-bg qa

Ferric ion forms a prussian blue coloured precipitate upon reaction with Potassium Ferrocyanide. This prussian blue compound is 

Option: 1

K_{4} F e(C N)_{6}


Option: 2

\mathrm{Fe}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]_{3}


Option: 3

\mathrm{KMnO}_{4}


Option: 4

\mathrm{Fe}(\mathrm{OH})_{3}


Answers (1)

best_answer

Ferric ions form a Prussian blue precipitate on reaction with Potassium Ferrocyanide. This is because of the formation of Ferric Ferrocyanide \mathrm{(Fe_4[Fe(CN)_6]_3)} 

4 \mathrm{FeCl}_{3}+3 \mathrm{~K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right] \rightarrow \mathrm{Fe}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]_{3}+12 \mathrm{KCl}

Hence, the correct answer is Option (2)

Posted by

Pankaj

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE