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Figure below shows a liquid being pushed out of the tube by a piston having area of cross section 2.0\; cm^{2}.The area of cross section at the outlet is 10\; mm^{2}.If the piston is pushed at a speed of 4cm\; s^{-1}.the speed of outgoing fluid is _________cm\; s^{-1}

Option: 1

80


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

By equation of continuity

\begin{aligned} & \mathrm{A}_1 \mathrm{~V}_1=\mathrm{A}_2 \mathrm{~V}_2 \\ & \left(2 \mathrm{~cm}^2\right)(4 \mathrm{~cm} / \mathrm{s})=\left(10 \times 10^{-2} \mathrm{~cm}^2\right)(\mathrm{v}) \\ & \frac{8 \mathrm{~cm}^3}{\mathrm{~s}}=10^{-1} \mathrm{~cm}^2(\mathrm{v}) \\ & \mathrm{V}=80 \mathrm{~cm} / \mathrm{s} \end{aligned}

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Ajit Kumar Dubey

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