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Figure below shows a network of resistance. The effective resistance between points A and B of network is:

Option: 1

\mathrm{\left ( \frac{3}{2} \right )\Omega}


Option: 2

\mathrm{6\: \Omega}


Option: 3

\mathrm{3\Omega}


Option: 4

\mathrm{2\Omega}


Answers (1)

Resistance of arm AFE =3+3=6 \Omega

The arms AFE and AE are in parallel, their effective resistance =\frac{6 \times 6}{6+6}=3 \Omega

Resistance of arm AED =3+3=6 \Omega

Effective resistance between A and D of portion AFED =\frac{6 \times 6}{6+6}=3 \Omega

Effective resistance between A and C of portion AFEDC =\frac{(3+3) \times 6}{(3+3)+6}=3 \Omega

Resistance of arm AFEDCB =3+3=6 \Omega

For resistance between A and B, 6 \Omega \text { and } 3 \Omega are in parallel.

Thus effective resistance \mathrm{R_p=\frac{3 \times 6}{3+6}=2 \Omega}

Posted by

Sumit Saini

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