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Figure shows a circuit in which three identical diodes are used. Each diode has forward resistance of 20\Omega and infinite backward resistance. Resistors R_{1}=R_{2}=R_{3}=50\Omega . Battery voltage is 6V. The current through R_{3} is : 

Option: 1

50\:\: mA


Option: 2

100\:\: mA


Option: 3

60\:\: mA


Option: 4

25\:\: mA


Answers (1)

best_answer

Here, diodes  D1 and  D2 are forv/ard biased and  D3 is reverse biased. Therefore current through R3

 

i=\frac{V}{R^{\prime}}=\frac{6}{120}=\frac{1}{20} A=50 mA

 

Posted by

vishal kumar

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