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  • Find the bisector of the angle containing the point (1,-2) between the lines <img alt="\mathrm{3 x-4 y= 0}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B3%20x-4%20y%3D%200%7D" /

Find the bisector of the angle containing the point (1,-2) between the lines \mathrm{3 x-4 y= 0} and \mathrm{5 x+12 y+7=0},
 

 

Option: 1

\mathrm{2 x+8 y+35=0}


Option: 2

\mathrm{64 x-16 y-5=0}


Option: 3

\mathrm{64 x+8 y+35=0}


Option: 4

\mathrm{2 x-16 y-5=0}


Answers (1)

best_answer

Equations of the bisectors are

\mathrm{\frac{3 x-4 y}{5}= \pm \frac{5 x+12 y+7}{13}}

i.e. \mathrm{2 x-16 y-5=0} and \mathrm{64 x+8 y+35=0}

Putting (1,-2) in the both given lines we get positive and negative values, so required angle bisector is \mathrm{64 x+8 y+35=0.}

Posted by

Pankaj

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