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  • Find the equation of the lines through the point which make an angle of <img alt="450

Find the equation of the lines through the point (2,3) which make an angle of 450 with the line 3x-y +5=0.

 

Option: 1

x+2y-4=0 \ and \ x+2y =7


Option: 2

x-2y+4=0 \ and \ 2x+y-7=0


Option: 3

x+2y-7=0 \ and \ 2x-y+4=0


Option: 4

none of these 


Answers (1)

best_answer

Let the equation of one such line is y-3=m(x- 2)
\mathrm{m}\ of\ the\ line\ 3 x-y+5=0\ is\ 3 \\ \therefore \frac{3-m}{1+3 m}=\tan 45^{\circ} \text { or } \tan 135^{\circ} \Rightarrow \frac{3-m}{1+3 m}=1 \text { or }-1 \\ i.e. m=\frac{1}{2} or -2 
\therefore The equations of the lines are, x - 2y + 4 = 0 & 2x + y = 7        

 

 

 

 

 

 

Posted by

seema garhwal

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