Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Find the locus of centre of the circle such that it touches the circle

Find the locus of centre of the circle such that it touches the circle \mathrm{x^2+y^2=1} externally and the line \mathrm{x+2=0.}

Option: 1

\mathrm{y^2=4(x+3)}


Option: 2

\mathrm{y^2=6 x+9}


Option: 3

\mathrm{y^2=4 x+6}


Option: 4

\mathrm{y^2=-\left(x+\frac{3}{2}\right)}


Answers (1)

best_answer

Let centre of the circle be \mathrm{C(h, k)}

Hence OC\mathrm{ =1+r=\sqrt{h^2+k^2}}

\mathrm{ \begin{aligned} & \text { and } r=\frac{|h+2|}{1}=(h+2) \\ & \Rightarrow \sqrt{h^2+k^2}=(h+3) \\ & \Rightarrow k^2=6 h+9 \end{aligned} }
Hence required locus is \mathrm{y^2=6\left(x+\frac{3}{2}\right).}

Posted by

Divya Prakash Singh

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

NEET, JEE Main 2026: Wondering which college, course to pick? Careers360’s offline counselling from April 19
anam-khan

JEE Main 2026 final key soon; objection window closes today
anam-khan

100 marks in JEE Mains 2026 Percentile: Know rank trends, admission chances at NITs, IIITs

Latest Question