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Find the net gravitational field intensity at the centroid of an equilateral triangle as shown in figure

 

 

Option: 1

\frac{\sqrt{3}GM}{l^{2}}
 


Option: 2

\frac{{3}GM}{l^{2}}
 


Option: 3

\frac{GM}{l^{2}}

 


Option: 4

\frac{\sqrt{2}GM}{l^{2}}


Answers (1)

best_answer

  

 

 

The resultant field at point 0 due to masses m and m 

E^{1}=\sqrt{E^{2}+E^{2}+2E.E.cos120^{0}}

E^{1}=E= \frac{Gm}{r^{2}}

Field due to mass 2m at point 0

E^{11}=\frac{2Gm}{r^{2}}=2E

Therefore net field 

=E^{11}-E^{1}

=2E-E

=E= \frac{GM}{r^{2}}=\frac{GM}{(\frac{l}{\sqrt{3}})^{2}}=\frac{3GM}{l^{2}} 

 

Posted by

chirag

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