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Find the phase difference of given LR circuit 

Option: 1

80.95


Option: 2

70.46


Option: 3

90


Option: 4

0


Answers (1)

best_answer

As we learned

Phase difference -

\tan \phi = \frac{X_{L}}{R}= \tan ^{-1}\left ( \frac{X_{L}}{R} \right )

\phi = \tan ^{-1}\left ( \frac{\omega L}{R} \right )

- wherein

XL  = inductive reactance

R     = resistance

 

 Find the phase difference of given LR circuit

Phase difference -

\tan \phi = \frac{X_{L}}{R}= \tan ^{-1}\left ( \frac{X_{L}}{R} \right )

\phi = \tan ^{-1}\left ( \frac{\omega L}{R} \right )

\phi = \tan ^{-1}\left ( \frac{2\pi f L}{R} \right )

\phi = \tan ^{-1}\left ( \frac{2\times\pi\times50\times0.2 \times 10^{-3}}{0.01} \right )

\phi = \tan ^{-1}\left ( 6.08 )

\phi = 80.95

 

Posted by

Devendra Khairwa

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