Browse by Stream
QnA
Home

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Find the phase difference of given LR circuit <div class='qn

Find the phase difference of given LR circuit 

Option: 1

80.95


Option: 2

70.46


Option: 3

90


Option: 4

0


Answers (1)

best_answer

As we learned

Phase difference -

\tan \phi = \frac{X_{L}}{R}= \tan ^{-1}\left ( \frac{X_{L}}{R} \right )

\phi = \tan ^{-1}\left ( \frac{\omega L}{R} \right )

- wherein

XL  = inductive reactance

R     = resistance

 

 Find the phase difference of given LR circuit

Phase difference -

\tan \phi = \frac{X_{L}}{R}= \tan ^{-1}\left ( \frac{X_{L}}{R} \right )

\phi = \tan ^{-1}\left ( \frac{\omega L}{R} \right )

\phi = \tan ^{-1}\left ( \frac{2\pi f L}{R} \right )

\phi = \tan ^{-1}\left ( \frac{2\times\pi\times50\times0.2 \times 10^{-3}}{0.01} \right )

\phi = \tan ^{-1}\left ( 6.08 )

\phi = 80.95

 

Posted by

Devendra Khairwa

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

In JEE Main 2025 April 3 shift 2, chemistry takes U-turn to be tougher than physics, mathematics
anam-khan

JEE Main 2025 April 3 Exam Analysis 2025: Shift 1 paper easy to moderate; chemistry section ‘easiest’
anam-khan

JEE Mains 2025 admit card out for April 7, 8, 9 exams; download on jeemain.nta.nic.in

Latest Question