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  • Find the sum of 4th and 6th terms of the series whose nth term is <img alt="\mathrm{(2 n-4) ! \times n}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B%282%20n-4%29%20%21%20%5Cti

Find the sum of 4th and 6th terms of the series whose nth term is \mathrm{(2 n-4) ! \times n}.

Option: 1

3,26,804


Option: 2

1,58,965


Option: 3

2,42,016


Option: 4

3,60,000


Answers (1)

best_answer

To find the sum of the 4th and 6th terms of the series with the nth term as (2 n-4) ! \times n,

we need to substitute the values of n = 4 and n = 6 into the given expression and then add them up.

For the 4th term (n=4):
(2(4)-4) ! \times 4=(4) ! \times 4

For the 6 th term (n=6):
(2(6)-4) ! \times 6=(8) ! \times 6

Now, let's calculate the values of (4) ! and (8) !
\text { (4)! }=4 \times 3 \times 2 \times 1=24

(8) !=8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1=40320
Now, let's find the sum of the 4th and 6th terms:
(4) ! \times 4+(8) ! \times 6=24 \times 4+40320 \times 6=96+241920=242016

Therefore, the sum of the 4 th and 6 th terms of the series is 242,016 .

 

Posted by

manish painkra

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