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Find the value of $\tan ^{-1}2+\tan^{-1}(-3)$
Option: 1
$\tan^{-1}(\frac{1}{5})$

Option: 2
$\pi+\tan^{-1}(\frac{1}{5})$

Option: 3
$\pi-\tan^{-1}(\frac{1}{5})$

Option: 4
$-\tan^{-1}(\frac{1}{5})$

Answers (1)

best_answer

$\\\tan ^{-1}(2)+\tan^{-1}(-3)\\ =\tan ^{-1}(2)-\tan^{-1}(3)\\ As\,\, x>0,y>0 \\=\tan^{-1}(\frac{2-3}{1-2\times 3})\\ \\ =\tan^{-1}(\frac{1}{5})$

Posted by

Ritika Jonwal

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