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Find the value of sec^{-1}\left ( -2 \right )

Option: 1

2 \pi / 3


Option: 2

\pi / 3


Option: 3

5 \pi / 6


Option: 4

\pi / 6


Answers (1)

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As we have learned

Important Results of Inverse Trigonometric Functions -

\sec ^{-1}\left ( -x \right )= \pi -\sec ^{-1}x

-

 

 

Trigonometric Ratios of Special Angles -

- wherein

These are the values of trigonometric ratios for standard angles. 

 

 \sec ^{-1}(-2) \\ = \pi - \sec ^{-1}(2) \\ = \pi - \frac{\pi }{3 } \\= \frac{2 \pi }{3}

 

 

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Rakesh

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