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  • For a given triode.  The load resistance is 1.5 times the anode resistance. The maximum gain will be<di

For a given triode. \mu=20 The load resistance is 1.5 times the anode resistance. The maximum gain will be

Option: 1

16


Option: 2

12


Option: 3

10


Option: 4

None of the above


Answers (1)

best_answer

Voltage gain \mathrm{A_v=\frac{\mu}{1+\frac{r_p}{R_L}} }

\mathrm{\because R_L=1.5 r_p \Rightarrow A_v=\frac{\mu}{1+\frac{r_p}{1.5 r_p}}=\frac{3}{5} \mu=\frac{3}{5} \times 20=12 }

Posted by

Sanket Gandhi

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