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  • For a periodic motion represented by the equation <img alt="y=\sin \omega t+\cos \omega t" src="https://entrancecorner.oncodecogs.com/gif.latex?y%3D%5Csin%20%5Comega%20t&plus;%5Ccos%20%5Co

For a periodic motion represented by the equation y=\sin \omega t+\cos \omega t the amplitude of the motion is

Option: 1

0.3


Option: 2

1


Option: 3

2


Option: 4

\sqrt{2}


Answers (1)

best_answer

If equation of SHM is in the form \mathrm{y}=\mathrm{a} \sin (\omega \mathrm{t})+\mathrm{B} \cos (\omega \mathrm{t})

Then its amplitude is =\sqrt{\mathrm{A}^2+\mathrm{B}^2}

Here A = B = 1 in equation y=\sin (\omega t)+(\cos \omega t)

Therefore, \text { Amplitude }=\sqrt{(1)^2+(1)^2}=\sqrt{2}

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Riya

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