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For a reaction \begin{aligned} \mathrm{2 P \rightarrow Q+3 R; if -\frac{d[P]}{d t}=k_1[p]^2, \frac{d[Q]}{d t}=k_2[P]^2 ; \frac{d[R]}{d t}=k_3[P]^2,} \end{aligned} the correct relation between\mathrm{ k_1, k_2} and \mathrm{ k_3} is:
 

Option: 1

\mathrm{ 2 k_1=k_2=3 k_2}


Option: 2

\mathrm{ k_1=k_2=k_3}


Option: 3

\mathrm{4 k_1=k_2=3 k_2}


Option: 4

\mathrm{\frac{k_1}{2}=k_2=\frac{k_3}{3}}


Answers (1)

best_answer

\begin{gathered} \mathrm{-\frac{1}{2} \frac{d[P]}{d t}=\frac{d[Q]}{d t}=\frac{1}{3} \frac{d[R]}{d t}} \\ \mathrm{\frac{k_1[P]^2}{2}=k_2[P]^2=\frac{1}{3} k_3[P]^2 }\\ \mathrm{\frac{k_1}{2}=k_2=\frac{k_3}{3}} \end{gathered}

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shivangi.shekhar

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