Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • For a rolling spherical shell, the ratio of rotational kinetic energy and total kinetic energy is <img alt="\frac{x}{5}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cfrac%7Bx%7D%7B5%7D"

For a rolling spherical shell, the ratio of rotational kinetic energy and total kinetic energy is \frac{x}{5} . The value of x is ____

Option: 1

2


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

 

\begin{aligned} & \mathrm{KE}_{\mathrm{Translational}} =\frac{1}{2} \mathrm{mV}^2 \\ & \mathrm{KE}_{\mathrm{Rotational}}=\frac{1}{2}\left(\frac{2}{5} \mathrm{mR}^2\right) \omega^2=\frac{1}{3} \mathrm{mR}^2 \cdot \frac{\mathrm{V}^2}{\mathrm{R}^2}=\frac{1}{3} \mathrm{mV}^2 \\ & \mathrm{KE}_{\mathrm{Total}}=\frac{1}{2} \mathrm{mV}^2+\frac{\mathrm{mV}^2}{3} \\ & \mathrm{KE}_{\mathrm{Total}}=\frac{5}{6} \mathrm{mV}^2 \\ & \frac{\mathrm{K}_{\mathrm{Rotational}}}{\mathrm{K}_{\mathrm{Total}}}=\frac{1 / 3 \mathrm{mV}^2}{5 / 6 \mathrm{mV}^2}=\frac{2}{5} \\ & \mathrm{x}=2 \end{aligned}

Posted by

Deependra Verma

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Latest Question