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  • For a series LCR circuit, I vs curve is shown : (a) To the left of , the circui

For a series LCR circuit, I vs \omega curve is shown :
(a) To the left of \omega_{r}, the circuit is mainly capacitive.
(b) To the left of \omega_{\mathrm{r}}, the circuit is mainly inductive.
(c) At \omega_{\mathrm{r}}, impedance of the circuit is equal to the resistance of the circuit.
(d) At \omega_{\mathrm{r}}, impedance of the circuit is 0 .


Choose the most appropriate answer from the options given below :

 

Option: 1

(a) and (d) only


Option: 2

(b) and (d) only


Option: 3

(a) and (c) only


Option: 4

(b) and (c) only


Answers (1)

best_answer

\mathrm{X_{C}=\frac{1}{\omega c}, X_{L}=\omega L}

If \mathrm{\omega =\omega_ r},

    \mathrm{x_{L}=x_{C}}

For \mathrm{\omega < \omega _{r}} capacitive

at \mathrm{\omega=\omega_{r}, x_{L}=x_{C}}

\mathrm{z=\sqrt{R^{2}+\left(x_{L}-x_{C}\right)^{2}}=R}

Hence, correct answer is Option (3)

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