Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • For a simple harmonic motion in a mass spring system shown, the surface is frictionless. When the mass of the block is <img alt="1 \mathrm{~kg}" src="https://entrancecorner.oncodecogs.com/gif.latex

For a simple harmonic motion in a mass spring system shown, the surface is frictionless. When the mass of the block is 1 \mathrm{~kg}, the angular frequency is \omega_{1}. When the mass block is 2 \mathrm{~kg} the angular frequency is \omega_{2}. The ratio \omega_{2} / \omega_{1} is

Option: 1

1 / \sqrt{2}


Option: 2

\sqrt{2}


Option: 3

2


Option: 4

1 / 2


Answers (1)

best_answer

\omega=\sqrt{\frac{k}{m}}
\frac{\omega_{2}}{\omega_{1}}=\sqrt{\frac{m_{1}}{m_{2}}}=\sqrt{\frac{1}{2}}
 

Posted by

Nehul

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 registration ends tomorrow; changes introduced in exam this year
anam-khan

BTech Admission 2025 Live: JEE Mains registrations closing tomorrow; VITEEE, MET exam dates out
anam-khan

JEE Main 2025 Live: NTA to close JEE registration on Friday; apply at jeemain.nta.nic.in, correction window

Latest Question