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  • For steel Y=2x1011 N/m2 . The force required to double the length of a steel wire of area 1 cm2 is -Option: 1

For steel Y=2x1011 N/m2 . The force required to double the length of a steel wire of area 1 cm2 is -

Option: 1

2x107 N


Option: 2

2x106 N


Option: 3

2x108 N


Option: 4

2x105 N


Answers (1)

best_answer

Young\: \: modulus(Y)=\frac{\frac{F}{A}}{\frac{\Delta L}{L}}=\frac{F}{A}

F = Y.A

   = 2 x 1011 x 10-4

   = 2 x 107 N

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Pankaj

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