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For the given cell; $Cu(s)Cu^{2+}(C_{1}M)\parallel Cu^{2+}(C_{2}M)\mid Cu(s)$ change in Gibbs energy $(\Delta G)$ is negative, if :
Option: 1 $C_{1}=C_{2}$
Option: 2 $C_{2}=\frac{C_{1}}{\sqrt{2}}$
Option: 3 $C_{1}=2 C_{2}$
Option: 4 $C_{2}=\sqrt{2} C_{1}$

Answers (1)

best_answer

We know this formula

Only $C_{2}=\sqrt{2} C_{1}$ following the above condition.

Therefore, the correct option is (4).

Posted by

Kuldeep Maurya

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