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For the given circuit the current through battery of 6 \mathrm{~V} just after closing the switch 'S' will be __________A.

Option: 1

1


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

Just after closing the circuit the inductor behaves as opent circuit (\infty resistance)

\mathrm{I=\frac{6v}{6\Omega }=1A}
The current through battery of \mathrm{6 \mathrm{~V} \, is \: I=1 \mathrm{~A}}

Posted by

Suraj Bhandari

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