Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • For the plane electromagnetic wave given by <img alt="\mathrm{E}=\mathrm{E}_0 \sin (\omega \mathrm{t}-\mathrm{kx})$ and $\mathrm{B}=\mathrm{B}_0 \sin (\omega t-k x)" src="https://entrancecorner.onc

For the plane electromagnetic wave given by \mathrm{E}=\mathrm{E}_0 \sin (\omega \mathrm{t}-\mathrm{kx})$ and $\mathrm{B}=\mathrm{B}_0 \sin (\omega t-k x), the ratio of average electric energy density to average magnetic energy density is

Option: 1

2


Option: 2

1/2


Option: 3

1


Option: 4

4


Answers (1)

best_answer

In EM waves, average electric energy density is equal to average magnetic energy density.
\frac{1}{4} \epsilon_0 E_0^2=\frac{1}{4 \mu_0} B_0^2

Posted by

vishal kumar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 registration ends tomorrow; changes introduced in exam this year
anam-khan

BTech Admission 2025 Live: JEE Mains registrations closing tomorrow; VITEEE, MET exam dates out
anam-khan

JEE Main 2025 Live: NTA to close JEE registration on Friday; apply at jeemain.nta.nic.in, correction window

Latest Question