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For the trannsistor the value of  α  is 0.8. The change in the collector current corresponding to a change of 4mA in the base current in a common base arrangment is:

Option: 1

16mA


Option: 2

72mA


Option: 3

18mA


Option: 4

54mA


Answers (1)

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\begin{aligned} & \therefore 0.8=\alpha \\ & \alpha=0.8=\frac{I_c}{I_\epsilon}=\frac{I_c}{\Delta I_c+\Delta I_B} \end{aligned}

\begin{aligned} & 0.8\left(\Delta I_c+4\right)=\Delta I_c \\ & 0.8 \Delta I_c+3.2=\Delta I_c \\ & 0.2 \Delta I_c=3.2 \\ & \Delta I_c=\frac{3.2}{0.2}=16 \mathrm{~mA} \end{aligned}

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