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For the transverse wave equation, y=A \sin (\pi x+\pi t), choose the correct option at t=0.

 

Option: 1

points at x=0 and x=1 are at mean position


Option: 2

points at x=0.5 and x=1.5 have max acc


Option: 3

points at x=0 and x=1.5 are at rest 


Option: 4

The given wave is traveling in the negative x direction


Answers (1)

best_answer

y=A \sin (\pi x+\pi t)

V_p=\frac{\partial y}{\delta t}=\pi A \cos (\pi x+\pi t)

a_p=\frac{\partial^2 y}{\delta t^2}=-\pi^2 A \sin (\pi x+\pi t)

Now, substitute t=0 and given value of x.

Since, \omega t and kx are of the same sign, hence the wave is traveling in the negative x-direction

 

Posted by

avinash.dongre

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