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Four condensers each of capacity 4\, \mu \mathrm{F} are connected as shown in figure \mathrm{v_{p}-V_{Q}=15} volts.
The energy stored in the system is -

Option: 1

2400 ergs.


Option: 2

1800 ergs.

 


Option: 3

 3600 ergs.


Option: 4

5400 ergs.


Answers (1)

best_answer

Equivalent circuit will be-


\mathrm{\frac{1}{C_{P Q}}=\frac{1}{4}+\frac{1}{8}+\frac{1}{4}=\frac{1}{2}+\frac{1}{8}=\frac{4+1}{8} }
\mathrm{C_{P Q}=\frac{8}{5} \mu F }

Now, store energy \mathrm{U=\frac{1}{2} c v^{2}}
                               \mathrm{=\frac{1}{2} \times \frac{8}{5} \times 15 \times 15}
                              \mathrm{=12 \times 15=180 \times 10^{-6}}
                              \mathrm{=1800 \text { ergs. }}   Ans.

Posted by

Riya

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