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Four distinct points (2 K, 3 K),(1,0),(0,1)$ and $(0,0) lie on a circle when

Option: 1

all are integral values of K


Option: 2

0<K<1


Option: 3

K<0


Option: 4

For two values of K


Answers (1)

best_answer

The equation of the circle passing through the point (1,0),(0,1)$ and $(0,0) is

\mathrm{x^{2}+y^{2}-x-y=0}, which passes through \mathrm{(2 k, 3 k)}, if

\mathrm{4 k^{2}+9 k^{2}-2 k-3 k=0 \Rightarrow k=0, k=\frac{5}{13}}.
Hence (D) is the correct answer.

Posted by

Anam Khan

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