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Four fair coins are lossed simultaneously. The probability that at least one heads and at least one tails furn up is

Option: 1

\frac{1}{16}


Option: 2

\frac{1}{8}


Option: 3

\frac{7}{8}


Option: 4

\frac{15}{16}


Answers (1)

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Probability of all head or all tails appearing

                             \begin{aligned} & \mathrm{=P(H H H H)+P(T T T)} \\ & =\frac{1}{16}+\frac{1}{16}=\frac{1}{8} \end{aligned}

P (at least one and one H and one T)

                              \begin{aligned} & =1-\mathrm{P(\text { all } H \text { or all } T)} \\ & =1-\frac{1}{8}=\frac{7}{8} \end{aligned}

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Nehul

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