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Four wires of same materials are stretched by the same load. The dimensions of the wire are given below.The one which has maximum elongation is:

 

Option: 1

Diameter 1\ mm and length 1\ m


Option: 2

Diameter 2\ mm and length 2\ m


Option: 3

Diameter 0.5\ mm and length 0.5\ m


Option: 4

Diameter 3\ mm and length 3\ m


Answers (1)

best_answer

\Delta l=\frac{F l}{A Y}

\text or \Delta l \propto \frac{1}{d^2}\left(A=\frac{\pi}{4} d^2\right)

Therefore, \Delta{l} will be the maximum for what wire for which {1}/{d^{2}} is maximum.

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