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Four wires of same materials are stretched by the same load. The dimensions of the wires are as given below. The one which has the maximum elongation is of -

Option: 1

Diameter 1mm and length 1m


Option: 2

Diameter 2mm and length 2m


Option: 3

Diameter 0.5mm and length 0.5m


Option: 4

Diameter 3mm and length 3m


Answers (1)

best_answer

\Delta l=\frac{F l}{A Y}

or \Delta l \propto \frac{1}{d^2}\left(A=\frac{\pi}{4} d^2\right)

Therefore, \Delta l will be maximum for what wire for which 1 / d^2 is maximum.

Posted by

Ritika Jonwal

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